Answer: correct option is the option B= 2.6 × 10^-5 mol.sec^-1
Step-by-step explanation:
Check attached file/picture for the plot of graph of reaction velocity against substrate concentration.
Initial velocity can be defined as the velocity at the beginning of an enzyme-catalyzed reaction. It is usually denoted as V°.
In the equation of reaction below;
A + B----------> [AB] ------------>Product
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Where the forward reaction is k1 that is the rection producing the intermediate [AB].
And, the backward reaction is k-1 that is the arrow pointing back to the Reactants.
K2 is the arrow from the intermediate [AB] to the products.
Note that k1 and k-1
represent rapid non-covalent dissociation of substrate from enzyme active site. Also, K2 is the rate constant for the formation of the products.
In order to calculate the initial velocity,V° we need to use the Michaelis- Menteen equation.
V° = Vmax ×(S)/ Km + (S)-------------------------------------------------------------(1).
From the question the parameters given are;
Vmax = 6.5 x 10–5 mol•sec–1 , [S] = 3.0 x 10–3 M, and KM = 4.5 x 10–3 M.
Therefore, slotting in the above parameters into the equation (1) above, we have;
V° = 6.5 x 10–5 mol•sec–1 × 3.0 x 10–3 M / 4.5 x 10–3 M + 3.0 x 10–3 M.
Initial velocity,V° = 2.6 x 10-5 moles per sec..