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An aluminum alloy tube with an outside diameter of 3.50 in. and a wall thickness of 0.30 in. is used as a 14 ft long column. Assume that E = 10,000 ksi and that pinned connections are used at each end of the column. Determine the slenderness ratio and the Euler buckling load for the column.

User Masta
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1 Answer

6 votes

Answer:

slenderness ratio = 147.8

buckling load = 13.62 kips

Step-by-step explanation:

Given data:

outside diameter is 3.50 inc

wall thickness 0.30 inc

length of column is 14 ft

E = 10,000 ksi

moment of inertia
= (\pi)/(64 (D_O^2 -D_i^2))


I = (\pi)/(64)(3.5^2 -2.9^2) = 3.894 in^4

Area
= (\pi)/(4) (3.5^2 -2.9^2) = 3.015 in^2


radius = \sqrt{(I)/(A)}


r = \sqrt{(3.894)/(3.015)

r = 1.136 in

slenderness ratio
= (L)/(r)


= (14 *12)/(1.136) = 147.8

buckling load
= P_cr = \frac{\pi^2 EI}}{l^2}


P_(cr) = (\pi^2 *10,000*3.844)/(( 14* 12)^2)


P_(cr) = 13.62 kips

User DSM
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