Answer:

Step-by-step explanation:
Given
resistance of the plant R =2.3 MΩ
separation between the electrode L= 20 cm
width of the leaf B= 2.1 cm
thickness t=0.20 mm
Area of the leaf= t×B
= 0.20 mm×2.1 cm=

Resistance of the leaf related to length and area


plugging values we get

