Answer:
(Z)-2-bromo-2-butene is produced here.
Step-by-step explanation:
Reaction of 2-butyne with one equivalent of HBr yields (Z)-2-bromo-2-butene.
In the first step, protonation of triple bond produces a carbocation with a double bond. Two methyl groups present in carbocation remain in opposite side to avoid steric interaction.
In the second step, a bromide ion gives nucleophilic addition reaction with carbocation to give (Z)-2-bromo-2-butene.
Full reaction mechanism has been shown below.