Question

Now imagine a person dragging a 50 kg box along the ground with a rope, as

in the drawing below. The person exerts 50 N of force while moving the box 201

10 s. Suppose also that friction is acting with 30 N of force between the box and the

ground

Answer 1

The coefficient of static friction between the box and floor is, μ = 0.061

Step-by-step explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

= 50 x 9.8

= 490 N

The coefficient of friction,

μ = f/ η

= 30 / 490

= 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061