Question

Consider the following code: public static void mystery(int a) { System.out.println("A"); } public static void mystery(double a) { System.out.println("B"); } public static void mystery(int a, double b) { System.out.println("C"); } public static void mystery(double a, int b) { System.out.println("D"); } What is output by the following? mystery(7);

Answer 1

The output is "A"

Step-by-step explanation:

public class Solution {

public static void main(String args[]) {

mystery(7);

}

public static void mystery(int a) { System.out.println("A"); }

public static void mystery(double a) { System.out.println("B"); }

public static void mystery(int a, double b) { System.out.println("C"); }

public static void mystery(double a, int b) { System.out.println("D"); }

}

In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.

In the first case; mystery will be called if the argument is int.

In the second case; mystery will be called if the argument is double.

In the third case; mystery will be called if the arguments are int and double.

In the fourth case; mystery will be called if the arguments are double and int.

When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".