Question

A 22.5 g sample of a metal is heated to 65.00 °C and added to 25.00 g of water (c = 4.184 J/g °C) in a calorimeter. The water temperature rises from 25.55 °C to 35.25 °C. What is the specific heat capacity of the metal?

Answer 1

The specific heat capacity of the metal is 1.143 J/g°C

Step-by-step explanation:

A typical excersise of calorimetry:

Q = m . C . ΔT

ΔT = Final T° - Initial T°

m = mass

In this case, the heat released by the metal is gained by the water to rise its temperature.

Qmetal = Qwater

(We consider that metal was at the same T° of water)

22.5 g . C . (65°C - 25.55°C) = 25 g . 4.184 J/g°C . (35.25°C - 25.55°C)

22.5 g . C . 39.45°C = 25g . 4.184 J/g°C . 9.7°C

887.625 g.°C . C = 1014.62J

C = 1014.62J / 887.625 g.°C

C = 1.143 J/g°C