Answer:
Option A (A and B have reached equilibrium concentrations)
Step-by-step explanation:
for the reaction
A→B , with ΔG'° = –60 kJ/mol
Since the presence of enzyme does not affect the equilibrium concentrations (ΔG is not affected ) , only affect the kinetics → option B is not possible.
For the same reason C is not possible since ΔG is related with the thermodynamics of the reaction ( equilibrium concentrations and feasibility) and not the kinetics.
Since the reaction always proceeds in direction of minimum ΔG , and the reaction lowers ΔG →the process is thermodynamically favorable → D and E are not possible
Since there is always at least a small conversion from pure reactants to products since the entropy increases when pure A is mixed with B ( entropy production due to mixing) , since also the process is thermodynamically favorable and besides the analysis reveals there was conversion from A to B → option A is the one that is more likely (A and B have reached equilibrium concentrations).