Step-by-step explanation:
For Copper
dH copper = mCdT copper
(Specific Heat of copper=0.385 J/g C )
dH = 500 g (0.385 J/g C) (78 C rise)
dH = 15,015 Joules
For Water
dH water = m C dT water
(Specific Heat of copper=4.184 J/g-C)
dH = 400 g (4.184 J/g-C) (78 C rise)
dH = 130,540 Joules
total heat = 15,015 + 130,540 = 145,555 Joules
Percentage for Water
(130,540 Joules / 145,555 Joules) x 100 = 89.7 %
If we consider that we have 3 Significant Figures,
then, the answers become ,
15.0 KJ must be added for Copper
130.5 KJ must be added for Water
and the total of 145 KJ must be added in the kettle with the water
89.7 % of heat goes to the Water