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2x-y-3z=7, 3x+y+=10, 5x+y+2z=15
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2 votes
2x-y-3z=7, 3x+y+=10, 5x+y+2z=15

User Darren Alfonso
by
6.7k points

2 Answers

2 votes

Explanation:

hope it helps you see the attachment

here I have used substitution method and also elimination method in one equation

2x-y-3z=7, 3x+y+=10, 5x+y+2z=15-example-1
2x-y-3z=7, 3x+y+=10, 5x+y+2z=15-example-2
2x-y-3z=7, 3x+y+=10, 5x+y+2z=15-example-3
User Mkll
by
5.7k points
3 votes
Y 50 I think it is I am not to sure
User Andrew MacNaughton
by
5.6k points
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