Answer: second option.
Explanation:
In order to solve this exercise, it is necessary to remember the following properties of logarithms:

In this case you have the following inequality:

So you need to solve for the variable "x".
The steps to do it are below:
1. You need to apply
to both sides of the inequality:

2. Now you must apply the properties shown before:

3. Then, rounding to the nearest ten-thousandth, you get:
