Explanation:
Given precision is a standard deviation of s=1.8, n=12, target precision is a standard deviation of σ=1.2
The test hypothesis is
H_o:σ <=1.2
Ha:σ > 1.2
The test statistic is
chi square =
![((n-1)s^2)/(\sigma^2)](https://img.qammunity.org/2020/formulas/mathematics/college/8gk1z36wjjdh5kadeiwb910gxjzlkesn7f.png)
=
![((12-1)1.8^2)/(1.2^2)](https://img.qammunity.org/2020/formulas/mathematics/college/tufru65yec67vj45utxx6zhifriljbvsnb.png)
=24.75
Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)
Since 24.75 > 3.05, we reject H_o.
So, we can conclude that her standard deviation is greater than the target.