Question

The circle below is centered at the point (4.1) and has a radius of length 2.What is its equation?

Answer 1

Hence the required equation of circle is

(x - 4)² + ( y - 1)² = 4

Explanation:

The equation of a circle whose center (h, k) and radius r is given-

(x - h)² + (y - k)² = r²

Here given that-

Center = ( 4, 1) & r = 2

Equation of circle-

( x - 4)² + ( y - 1)² = 2²

(x - 4)² + ( y - 1)² = 4

x² + 16 - 8 x + y² + 1 - 2 y = 4

x² + y² -8 x - 2 y + 13 = 0

Hence the required equation of circle is

(x - 4)² + ( y - 1)² = 4

0R

x² + y² - 8 x - 2 y + 13 = 0