Answer:
![P(S|\bar{C} ) = 0.1739](https://img.qammunity.org/2020/formulas/mathematics/high-school/prcia9fgjd8kyxh0viqe39l4ninbdwzx3u.png)
Explanation:
We define the probabilistic events how:
S: Today is snowing
C: The class is canceled
If it is snowing, there is an 80% chance that class will be canceled, it means
P( C | S ) = 0.8 conditional probability
If it is not snowing, there is a 95% chance that class will go on
![P( \bar{C} | \bar{S}) = 0.95](https://img.qammunity.org/2020/formulas/mathematics/high-school/csyzjo08zk5fxcg45qvw5hnptnx0o1w1cf.png)
and P(S) = 0.05
We need calculate
![P( S |\bar{C} ) = \frac{P(\bar{C} | S) P(S)}{P(\bar{C})}](https://img.qammunity.org/2020/formulas/mathematics/high-school/3wi397klqn7qwgs932udj858rqlwh7gyga.png)
![P(\bar{C}) = P( \bar{C}|S)P(S) + P( \bar{C}|\bar{S})P(\bar{S})](https://img.qammunity.org/2020/formulas/mathematics/high-school/jx4h5bceik8dt2z7v5gnf3wyjn1f9qhe69.png)
How
then
![P( \bar{C} | S) = 0.2](https://img.qammunity.org/2020/formulas/mathematics/high-school/5q09i103364sw5m9wg685gxiql8r0fbjey.png)
= (0.2)(0.5) + (0.95)(0.5)
=0.575
![P(S |\bar{C} ) = ((0.2)(0.5))/((0.575))](https://img.qammunity.org/2020/formulas/mathematics/high-school/rppo8p8nuesisvo3qat3nfb71esoxpg7jl.png)
![P(S|\bar{C} ) = 0.1739](https://img.qammunity.org/2020/formulas/mathematics/high-school/prcia9fgjd8kyxh0viqe39l4ninbdwzx3u.png)