Question

A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he releases it. Use conversation of energy to find

Answer 1

Step-by-step explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

We need to find the ball's maximum height above the ground. It can be calculated using the conservation of energy as :

`(1)/(2)mv^2=mgh'`

`h'=(v^2)/(2g)`

`h'=((10)^2)/(2* 9.8)`

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters. Hence, this is the required solution.