Answer:
The age of youngest brother is 21.
Explanation:
Given:
The ages of 3 brothers are represented by consecutive integers.
If the oldest brother's age is decreased by twice the younger brother's age, the result is -19.
Now, to find the age of youngest brother.
Let the age of youngest brother be
![a-1.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gxbweku3115gqs3mavwgnut4li8s1g4fal.png)
Let the age of middle one be
.
And the age of oldest brother age be
![a+1.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4n3l4635e7z4y5zaxbskukodsg9w19216c.png)
According to question:
![(a+1)-2(a-1)=-19](https://img.qammunity.org/2020/formulas/mathematics/middle-school/czlvdjfavsxqw8ld8b0enblb3aax83mgep.png)
⇒
![a+1-2a+2=-19](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v5p9m395thloxyt1k5yqpkhg8879p3v6cj.png)
⇒
![-a+3=-19](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hix32y5mt5ehr901ej4qo66sraq0wp4kdd.png)
Adding
on both sides we get:
⇒
![2=-19+a](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ek0vupv25ljjogy1lpt628jgx9rfnjh6f0.png)
Adding 19 on both sides we get:
⇒
![22=a](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d49px7tpwxtxw56dlxjny63opa1dtqq9h4.png)
Now, getting the age of youngest brother by putting the value of
:
![a-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hjs2vuxito7m7qufaywoqp5mxczu6bav6b.png)
⇒
![=22-1=21.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nzt446bltrmobjx02ggaotayg25cq6wouh.png)
Therefore, the age of youngest brother is 21.