Question

A 5.0-kg cannonball is fired over level ground with a velocity of 2.00 ⨯ 102 m/s at an angle of 25° above the horizontal. Just before it hits the ground its speed is 150 m/s. Over the entire trip, find the change in the thermal energy of the cannonball and air.

Answer 1

E=147898.01J

Step-by-step explanation:

A 5.0-kg cannonball is fired over level ground with a velocity of 2.00 ⨯ 102 m/s at an angle of 25° above the horizontal. Just before it hits the ground its speed is 150 m/s. Over the entire trip, find the change in the thermal energy of the cannonball and air

firstly , we look for the time of flight it takes to make the projectile path

T=2Usin∅/g

take g= 9.81m/s

T=2*200sin25/(9.81)

T=17.23Secs

energy is force *distance

E=f*d

f=m*g

f=5*9.81

f=49.05N

s=distance

s=(v+u)T/2

s=(150+200)17.23/2

s=3015.25m

49.05N*3015.25m

E=147898.01J