Question

I drop an egg from a certain distance and it takes 3.74 seconds to reach the ground. How high up was the egg?

Answer 1

68.5 meters

Step-by-step explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3.74 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0) (3.74) + ½ (9.8) (3.74)²

Δy = 68.5

The egg fell 68.5 meters.