Answer:
a) p is normally distributed with mean P = 0.4 and standard deviation
δ = 0.05477
b) P( 0.3 < p < 0.5) = 0.9312
Explanation:
a) What is the sampling distributión of P?
p(sample proportion) is normally distributed with mean P and standard
deviation δ =
![\sqrt{(P(1-P))/(n) }](https://img.qammunity.org/2020/formulas/mathematics/high-school/ou03y16k8psizysvpov9kn87oiupxsyown.png)
how P = 0.40 population proportion of the students live in dormitories,
then p is normally distributed with mean P = 0.4 and standard deviation
δ =
![\sqrt{(0.4(1-0.4)/(80) }](https://img.qammunity.org/2020/formulas/mathematics/high-school/x7qs1doph5w44ap42m460zl3rlmjeatypi.png)
δ = 0.05477
b) P( 0.3 < p < 0.5)
Standardizing
z = (p - P)/δ
![z_(1) = (0.3-0.4)/(0.05477)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3hujc10icj6vq1jldsp1uw1ea8ne5zz4bf.png)
= -1.82
![z_(2) = (0.5-0.4)/(0.05477)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rfe6dp3p08arbledyk6f3g4d90mmohne5o.png)
= 1.82
P(-1.82 < z < 1.82) = P(z < 1.82) - P(z<-1.82)
=0.9656 - 0.0344
P(-1.82 < z < 1.82) = 0.9312