Answer:
Explanation:
Given that Student scores on exams given by a certain instruc-tor have mean 74 and standard deviation 14.
Group I X Group II Y
Sample mean 74 74
n 25 64
Std error (14/sqrtn) 2.8 1.75
a) P(X>80) =
![1-0.9839\\= 0.0161](https://img.qammunity.org/2020/formulas/mathematics/college/jjhjm16e0ea57ndnez9ajd1wnchxl1m8fn.png)
b) P(Y>80) =
![1-0.9997\\=0.0003](https://img.qammunity.org/2020/formulas/mathematics/college/jvyzaczgyk84ecm8gpri5xhie9utq7fzf4.png)
c) X-Y is Normal with mean = 0 and std deviation =
![√(2.8^2+1.75^2) \\=3.302](https://img.qammunity.org/2020/formulas/mathematics/college/w1s6alk6bswnkjib9grw6pcg1lhhoujmv2.png)
P(X-Y>2.2) =
![1-0.8411\\=0.1589](https://img.qammunity.org/2020/formulas/mathematics/college/19z236ngk5zza18p8fplk1vg2pyeq0elox.png)
d)
![P(\bar x -\bar Y>2.2) = 0.1589](https://img.qammunity.org/2020/formulas/mathematics/college/vffk33pv6g6v8dw8c97zykexnsc1huhpxp.png)