Answer:
Figure show the equation of line : y=
![(-2)/(3) x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pul9fdwc6jied7t03jsbab01xzp6muoikw.png)
Explanation:
Given equation of line is y=
![(-2)/(3) x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pul9fdwc6jied7t03jsbab01xzp6muoikw.png)
To plot the equation of line:
For equation of line, we need at least two points
Let x=0
y=
![(-2)/(3) x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pul9fdwc6jied7t03jsbab01xzp6muoikw.png)
y=
![(-2)/(3)0+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cchyg1emqsg7tv8931f28s6lg17xh4r4ku.png)
y=1
The required point is (0,1)
Let x=3
y=
![(-2)/(3) x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pul9fdwc6jied7t03jsbab01xzp6muoikw.png)
y=
![(-2)/(3)3+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7sgw3pkh2agd0m2ln13akj5vvx3lxyvq1c.png)
y=(-1)
The required point is (3,-1)
Using points (0,1) and (3,-1) to plot the graph.
Figure show the equation of line : y=
![(-2)/(3) x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pul9fdwc6jied7t03jsbab01xzp6muoikw.png)