Question

87/The alcohol content of hard liquor is normally given in terms of the "proof," which is defined as twice the percentage by volume of ethanol (C2H5OH) present. Calculate the number of grams of alcohol present in 1.00 L of 87-proof gin. The density of ethanol is 0.798 g/mL.

Answer 1

334.08 g

Step-by-step explanation:

87 proof = 43.5%

in 1L of liquid there is 43.5% alcohol/ethanol

1L (43.5/100) = 0.435 L alcohol

we want density in g/L because that's the volume u have

density 0.798 g/mL = 798 g/L

multiply the volume of alcohol by its density to get grams

0.435 L(798 g/L) = 334.08 g