Question

1. Simplify 43x2y4)

- Show your work
(2x2,5)". Sho
Answer:
27 over
4x^2y^8

Answer 1

`$ (27)/(4x^6y^8) $`

Explanation:

Given:

`$ (4(3x^2y^4)^3)/((2x^3y^5)^4) $`

`$ (a^b)^c = a^(b.c) $` and

`$ (x^a)/(x^b) = x^(a - b) $`

We use the above two rules to solve the problem.

So,
`$ (4 (3^4 . x^6 . y^(12)))/(2^4. x^(12) .y^(20)) $`

`$ \implies (3^3. x^6. y^(12))/(2^2. x^(12). y^(20)) $`

Using the second rule we get:

`$ (3^3)/(2^2. x^6. y^(12))$`

`$ = (27)/(4. x^6. y^8) $`

Hence, the answer.