Question

In order to get lots of helium into tanks to fill kiddy balloons, they put force or pressure onto it. If i have 595 liters of helium at 1.00 atmosphere of pressure (that’s normal air pressure, or the pressure of the air), then what volume would it have if i applied 55.0 atmospheres of force or pressure to it?

Answer 1

1.90 L

Step-by-step explanation:

Using Boyle's law

`{P_1}* {V_1}={P_2}* {V_2}`

Given ,

V₁ = 595 L

V₂ = ?

P₁ = 1.00 atm

P₂ = 55.0 atm

Using above equation as:

`{P_1}* {V_1}={P_2}* {V_2}`

`{1.00}* {595}={55.0}* {V_2}`

`{V_2}=\frac{{1.00}* {595}}{55.0}\ L`

`{V_2}=1.90\ L`

The volume would be 1.90 L.