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the first five terms of a sequence are 7,10,13,16, and 19. Which of the following functions define this sequence for all the integers n>1

User Miguelgraz
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1 Answer

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The first five terms of a sequence are 7,10, 13 , 16 and 19. which of the following functions define this sequence for all integers n>or equal to 1?

A. f[n]= 3n=7

B.f[n]= 4+3n

C. f[n]= 4[3]^n-1

D.f[n]=7[3]^n-1

Answer:

Option B is correct.


f(n)=4+3n

Explanation:

Given:

The given sequence of an AP is.

7,10,13,16,19......

The first term of an AP
a=7

And common difference
d=10-7=3

The function which defined this sequence is;


f(n)=a_(n)=a+(n-1)d

Now we substitute a and d value in above equation.


f(n)=7+(n-1)3


f(n)=7+3n-3


f(n)=4+3n

therefore, the function for the given sequence for all integers
n\geq 1 1 is;
f(n)=4+3n

User Royconejo
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