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3 votes
What are the zeros of the following function?
y=x^2+x- 12

User Abedron
by
6.1k points

1 Answer

3 votes

Answer:

-4, 3.

Explanation:

x^2 + x - 12 = 0

(x + 4)(x - 3) = 0

x = -4, 3.

User Incalite
by
6.2k points