Question

A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s 2 . What is the magnitude of the mechanical energy lost due to friction acting on the runner?

Answer 1

`147.653J = W_f`

Step-by-step explanation:

We know that:

`E_i - E_f = W_f`

where
`E_i` is the initial energy,
`E_f` is the final energy and
`W_f` is the energy lost due to friction.

so:

`(1)/(2)MV^2-0 = W_f`

Where M is the mass and V is the velocity of the runner, so:

`(1)/(2)(68.2kg)(4.33m/s)^2 = W_f`

`147.653J = W_f`