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I need help on this problem-example-1

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Answer:
QR=4.04

Explanation:

For this exercise you must use the followinG Trigonometric Identity:


tan\alpha=(opposite)/(adjacent)

In this case, given the right triangle PQR, you can identify that:


\alpha=60\°\\opposite=PR=7.0\\adjacent=QR

Then, the next step is to substitute those values into
tan\alpha=(opposite)/(adjacent):


tan(60\°)=(7.0)/(QR)

And the final step is to solve for "QR" in order to find its value.

So you get that this is:


(QR)(tan(60\°))=7.0\\\\QR=(7.0)/(tan(60\°))\\\\QR=4.04

User Chris Laskey
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