Question

A reaction is performed in a vessel attached to a closed-tube manometer. Before the reaction, the levels of mercury in the two sides of the manometer were at the same height. As the reaction proceeds, a gas is produced. At the end of the reaction, the height of the mercury column on the vacuum side of the manometer has risen 43.96 cm and the height on the side of the manometer connected to the flask has fallen by the same amount. What is the pressure in the apparatus at the end of the reaction?

Answer 1

879.2 mmHg = 879.2 Torr = 1.16 atm

Step-by-step explanation:

A mercury manometer measures the pressure by the difference of the height in the two mercury columns. In this case, if one column had decreased, and the other one increased, the high difference will be 2x43.96 cm = 87.92 cm = 879.2 mm.

Thus, the pressure is equal to 879.2 mmHg, or 879.2 Torr.

1 atm ----- 760 Torr

x ----- 879.2 Torr

By a simple direct three rule

760x = 879.2

x = 1.16 atm