Question

How do i apply the pythagorean theorem and solve ?

Answer 1

3.
`{a}^(2) + {b}^(2) = {c}^(2) \\ {90}^(2) + {2}^(2) = {c}^(2) \\ 1800 + 4 = {c }^(2) \\ 1804 = {c}^(2) \\ √(1804) = {c}^(2) \\ {c}^(2) = \sqrt[2]{451} = 42.47`

4.
`{2}^(2) + {4}^(2) = {c}^(2) \\ 4 + 16 = {c }^(2) \\ 20 = {c}^(2) \\ {c}^(2) = \sqrt[2]{5} = 4.47`

Answer 2

3 IS 127.28 5 IS 4.47

Explanation:

A^2+B^2=C^2 then you use a calculator and square root C^2 to get your final answer.