Answer:
The required equation for the given point and the given slope is
![y+3=-(1)/(4)(x-8)](https://img.qammunity.org/2020/formulas/mathematics/high-school/67c3fq00f0h32z5iqf4msq42ceownwqmxh.png)
Explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( 8 ,-3)
To Find:
Equation of Line Passing through A( x₁ , y₁) with slope = -1/4
Solution:
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
![(y-y_(1))=m(x-x_(1))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y5ewrwnf2flptid2s377pb6onmd4zjoxdn.png)
Now on substituting the slope and point A( x₁ , y₁) ≡ ( 8 ,-3) we get
![(y-(-3))=-(1)/(4)(x-8)\\ \\y+3=-(1)/(4)(x-8)\ \textrm{which is the required equation in the option 2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/flze8u1u3l6cna3aulaflw7s2u08jyeh8y.png)
The required equation for the given point and the given slope is
![y+3=-(1)/(4)(x-8)](https://img.qammunity.org/2020/formulas/mathematics/high-school/67c3fq00f0h32z5iqf4msq42ceownwqmxh.png)