Question

Equation of the line that passes tjrougj the points of (0,-3) (1,-5)

Answer 1

y=-2x-3

Explanation:

m=(y2-y1)/(x2-x1)

m=(-5-(-3))/(1-0)

m=(-5+3)/1

m=-2/1

m=-2

y-y1=m(x-x1)

y-(-3)=-2(x-0)

y+3=-2(x)

y+3=-2x

y=-2x-3