1 Answer

Avinash Pande · Answer 1 · 2020-12-01T13:55:53+0000

Answer: The daughter nuclide formed by the beta decay of given isotope is
$_(39)^(89)\textrm{Y}$

Step-by-step explanation:

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

$_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta$

We are given:

Parent isotope =
$_(38)^(89)\textrm{Sr}$

The chemical equation for the beta decay process of
$_(38)^(89)\textrm{Sr}$ follows:

$_(38)^(89)\textrm{Sr}\rightarrow _(39)^(89)\textrm{Y}+_(-1)^0\beta$

Hence, the daughter nuclide formed by the beta decay of given isotope is
$_(39)^(89)\textrm{Y}$

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