Question

NASA launches a rocket at

t
=
0
t
=
0
seconds. Its height, in meters above sea-level, in terms of time is given by
h
=
−
4.9
t
2
+
259
t
+
423
h
=
-
4.9
t
2
+
259
t
+
423
.

How high is the rocket after 8 seconds?

meters

How high was the rocket when it was initially launched?

meters

Answer 1

Explanation

Height for time = 8 seconds

h = -4.9t^2 + 259t + 423

h = -4.9(8)^2 + 259(8) + 423

h = -313.6 + 2072 + 423

h = 2181.4 meters at 8 seconds

Heoght for time = 0 seconds

h = -4.9t^2 + 259t +423

h = -4.9(0)^2 + 259(0) + 423

h = 0 + 0 + 423

h = 423 meters at 0 seconds