Question

Suppose that a large pumpkin empty a swimming pool in 40 hours and that a small pumpkin empty a pool and 70 hours working together how long will it take to empty the pool

Answer 1

Total 25.45 hours will be taken to empty the pool.

Explanation:

Time taken by large pumpkin to empty the pool=40 hours

Time taken by the smaller pumpkins to empty the pool=70 hours

Amount of pool emptied by large pumpkin in one hour=
`(1)/(40)`

Amount of pool emptied by small pumpkin in one hour=
`(1)/(70)`

Amount of pool emptied in one hour if both pumpkins work together=

`(1)/(40)`+
`(1)/(70)`

=
`(11)/(280)`

Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie .
`(280)/(11)`

Total 25.45 hours will be taken to empty the pool.