Question

Find k so that the three equations 3x-y=2, 2x+8=3y and y=kx common solution

Answer 1

`k=2`

Explanation:

Given:-

`3x-y=2`----------------(Equation 1)

`2x+8=3y`-------------(Equation 2)

By solving Equation 1 we get,

`3x-y=2`

`y=3x-2`---------------(Equation 3)

Now substituting equation 3 in equation 2,

`2x+8=3y`

`2x+8=3\time (3x-2)`

`2x+8=9x-6`

`7x=14`

`x=2`---------------(Equation 4)

Now substituting equation 4 in equation 3 we get,

`y=3x-2`

`y=(3* 2)-2`

`y=6-2`

`y=4`--------------(Equation 5)

Now,

`y=kx`

`k=(y)/(x)`

`k=(4)/(2)`

`k=2`

Therefore
`k=2`