Question

A circuit with current increasing at a rate of 4 A/s contains an inductor, L. If the induced emf is -2 V, what is the inductance of the inductor?

Answer 1

L=500 mH

Step-by-step explanation:

Here di/dt = 4A/s, ε= -2V

Inductance of inductor, induced emf and rate of change of current have the following relation.

ε=
`- L(di)/(dt)`

⇒L= - ε/
`(di)/(dt)`

⇒L= -(-2)/ 4

⇒ L= 0.5 H or

⇒ L= 500 mH