Question

A sister spins her brother in a circle of radius R at angular speed wi. Then the sister decreases her angular speed

to wi, with the same radius. How does the magnitude of the brother's centripetal acceleration change when the
sister slows down?

Answer 1

Decreases by factor of 16

Step-by-step explanation:

khan acadamy

Answer 2

The change in the centripetal acceleration of the brother,

Δa = V₂²/R - V₁²/R

Step-by-step explanation:

Given data,

A sister spins her brother in a circle of radius, R

The angular velocity of the brother, ω₁ = V₁/R

The angular velocity of the brother, ω₂ = V₂/R

The centripetal acceleration is given by the relation

a = V²/R

Therefore change in the centripetal acceleration of the brother,

Δa = V₂²/R - V₁²/R