Answer:
54. 461.58 sq. ft.
55. 4.52 sq. ft.
Explanation:
54.
The figure is 3/4th of a full circle. We can find the area of the whole circle and multiply that by
to get our answer.
The area of a circle is given by:
![\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69e2ijkvwardlu2n5rrgtkpqc3b44mcw34.png)
Where r is the radius
The figure shows a radius of 14 feet, so we replace r with 14 and find the area (A):
![A=\pi r^2\\A=(3.14)(14)^2\\A=615.44](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qlueuj27nydkqpk2pb38hafimeo765i06c.png)
The area of this figure is:
![((3)/(4))*615.44\\=461.58](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lx8l788ykl0mfsqu82jflp9exlq8hthmiz.png)
The area is 461.58 sq. ft.
55.
The figure consists of 2 semicircle with diameter 2.4 shown.
The radius is half of diameter, so the radius (r) is:
r = 2.4/2 = 1.2 ft
The two semicircles match up together to form 1 whole circle. The area of a circle is given by:
![A=\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j29wdsg40jbed167khn7fs44y2z9velxu7.png)
Where
A is area
r is radius
This figure's area is area of whole circle with radius 1.2
So the area is:
![A=\pi r^2\\A=(3.14)(1.2)^2\\A=4.52](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8abjj1k531zoifm5a27v9g1qj6n2o7shsa.png)
The area of figure is 4.52 sq. ft.