Question

Hanging from a horizontal beam are nine simple pendulums of the following lengths:

(a) 0.10 m,
(b) 0.30 m,
(c) 0.40 m,
(d) 0.80 m,
(e) 1.2 m,
(f) 2.8 m,
(g) 3.5 m,
(h) 5.0 m, and
(i) 6.2 m. Suppose the beam undergoes horizontal oscillations with angular frequencies in the range from 2.00 rad/s to 4.00 rad/s. Which of the pendulums will be (strongly) set in motion?

Answer 1

Options d and e

Step-by-step explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

`L =(g)/(w^(2) )`

where g=9.8m/s

ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

`L= (9.8)/(2^(2) )`

L = 2.45m

when ω= 4rad/sec

`L=(9.8)/(4^(2) )`

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead