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In ∆ABC, m∠ACB = 90°, m∠A = 40°, CD (D ∈ AB ) is a segment perpendicular to side AB . Find m∠DBC and m∠BCD.

User Thomdask
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2 Answers

5 votes

Answer:

m∠B=50 degrees

m∠DBC=50 degrees(i think)

m∠BCD=40 degrees

Explanation:

User BlueTrin
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8.3k points
4 votes

Explanation:

sorry I'm late. I'm answering cause I felt bad abt the fact that noone answered u. Have a great morning or night!

User Chet Meinzer
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7.3k points