Question

A force of 10 N stretches a particular spring by 2 cm. How far would a 20 N force stretch that same spring? A force of 10 N stretches a particular spring by 2 cm. How far would a 20 N force stretch that same spring?

a. 20 cm
b. 4 cm
c. 8 cm
d. 2 cm

Answer 1

`x_2=4\ cm`

Step-by-step explanation:

Given that,

Force acting on the spring,
`F_1=10\ N`

Stretching in the spring,
`x_1=2\ N`

Force acting on the spring,
`F_2=20\ N`

Stretching in the spring,
`x_1=?`

To find :

How far would a 20 N force stretch that same spring?

Solution,

For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :

F=kx

`(F_1)/(x_1)=(F_2)/(x_2)`

`(10)/(2)=(20)/(x_2)`

`x_2=4\ cm`

Hence, the 20 N force stretch by 4 cm.