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18 votes
18 votes
From 12.5 liters of coolant containing 13.4% antifreeze, 5.50 liters are removed.

If 5.50 liters of pure antifreeze is then added, how much
antitreeze will be con
tained in the fina mixture?

User Zylstra
by
3.0k points

1 Answer

8 votes
8 votes

Answer:

6.438 [litres].

Explanation:

1) the condition '5.50 liters are removed' means the coolant 12.5-5.5=7 [litres] with 13.4% solution;

2) the condition 'coolant containing 13.4% antifreeze' means 7*0.134=0.938 [litres] of pure antifreeze in the 7 litres coolant;

3) the condition '5.50 liters of pure antifreeze is then added' means 0.938+5.5 [litres];

4) finally, it is contained 0.938+5.5=6.438 [litres] of antifreeze will be contained in the final mixture.

User Catandmouse
by
2.9k points
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