Answer:
S)No solution
T)Infinite solution
U)x=0
V)No solution
W) -1.2
X) No solution
Explanation:
For solving linear equations of one variable, take variable on one side and constants on one side.
S)
![(-1)/(3)(x) - (1)/(2) = (-1)/(3)(x) +12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yt40th5jbu1mysspq70j96dssrbm8vsrhp.png)
, this is false.
thus, for what ever value of x, this is false, thus, no solution.
T)
![(-5)/(6)(x) +40 = 40 + (-5)/(6)(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2o5rmncy7szu0a2i4j5am61992zpvsypgb.png)
, this is true.
thus, for what ever value of x, this is true, thus, infinite solutions.
U)
![(-10)(x) = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2at8cmmhl529zj37tflcwbtvf5fri71oba.png)
Thus, x= 0.
V)
,
this is false.
thus, for what ever value of x, this is false, thus, no solution
W)
![(5)/(6)(x) = -1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjyuvaiovw32v9hq42u13cyfj64krpbxn9.png)
![x = (-6)/(5) = -1.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qnqkz77734yp4ktt521t9dx1ilcwoj22he.png)
X)
![8x -5 = 6x+2+2x = 8x +2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/epw5yp0kmiafxsv8zhcglc4kph57fasogw.png)
, which is false.
thus, for what ever value of x, this is false, thus, no solution.