Question

The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). What is the angular acceleration at t = 5 s?The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). What is the angular acceleration at t = 5 s?'

Answer 1

Answer:
`\alpha =30-4=26 rad/s^2`

Step-by-step explanation:

Given

Position of a car is given by

`\theta =t^3-2t^2-4t+10`

and angular speed is
`\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega`

angular acceleration is

`\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha`

`\alpha =6t-4`

at
`t=5 s`

`\alpha =30-4=26 rad/s^2`