Question

A bag contains 3 red marbles, 2 blue marbles and 6 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be green?

Answer 1

P(A) = 20 %

Explanation:

let S be the sample space of the experiment,

n(S) = 3 red marbles +2 blue marbles +6 green marbles

∴ n(S) = 11

let A be the event of getting both the marbles drawn as a green marbles

∴ n(A) = 2

∴
`Probability(A)=(n(A))/(n(S)) \\\\P(A) =(2)/(11) \\\\P(A) = 0.1818\\\\P(A) = 0.2`

P(A) = 0.2 × 100 = 20%