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What are the coordinates of the point on the directed line segment from (-4, - 7) to

(-3,1) that partitions the segment into a ratio of 2 to 3?

User Sharrod
by
6.0k points

1 Answer

4 votes

Answer:

The coordinates of the point on the directed line segment from (-4, - 7) to

(-3,1) that partitions the segment into a ratio of 2 to 3 is


\therefore P(x,y)=((-18)/(5),(-19)/(5))

or

∴ PointP( x , y ) = ( -3.6, -3.8)

Explanation:

Let he points be,

point A( x₁ , y₁) ≡ ( -4 ,-7)

point B( x₂ , y₂) ≡ (-3 , 1)

and Point P( x , y ) be the point on the line Segment AB Divides AB internally in the ratio 2 : 3 i. e m : n

To Find:

Point P( x , y ) = ?

Solution:

IF a Point P divides Segment AB internally in the ratio m : n, then the Coordinates of Point P is given by Section Formula as


x=((mx_(2) +nx_(1)) )/((m+n))\\ \\and\\\\y=((my_(2) +ny_(1)) )/((m+n))\\\\

Substituting the Given values we get


x=((2(-3) +3(-4)) )/((2+3))\\ \\and\\\\y=((2(1) +3(-7)) )/((2+3))\\\\x=(-18)/(5)\\ \\and\\\\y=(-19)/(5)\\\\\therefore P(x,y)=((-18)/(5),(-19)/(5))

∴ PointP( x , y ) = ( -3.6, -3.8)

User Dennis Kaselow
by
6.4k points
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