132k views
2 votes
What are the coordinates of the point on the directed line segment from (-4, - 7) to

(-3,1) that partitions the segment into a ratio of 2 to 3?

User Sharrod
by
7.3k points

1 Answer

4 votes

Answer:

The coordinates of the point on the directed line segment from (-4, - 7) to

(-3,1) that partitions the segment into a ratio of 2 to 3 is


\therefore P(x,y)=((-18)/(5),(-19)/(5))

or

∴ PointP( x , y ) = ( -3.6, -3.8)

Explanation:

Let he points be,

point A( x₁ , y₁) ≡ ( -4 ,-7)

point B( x₂ , y₂) ≡ (-3 , 1)

and Point P( x , y ) be the point on the line Segment AB Divides AB internally in the ratio 2 : 3 i. e m : n

To Find:

Point P( x , y ) = ?

Solution:

IF a Point P divides Segment AB internally in the ratio m : n, then the Coordinates of Point P is given by Section Formula as


x=((mx_(2) +nx_(1)) )/((m+n))\\ \\and\\\\y=((my_(2) +ny_(1)) )/((m+n))\\\\

Substituting the Given values we get


x=((2(-3) +3(-4)) )/((2+3))\\ \\and\\\\y=((2(1) +3(-7)) )/((2+3))\\\\x=(-18)/(5)\\ \\and\\\\y=(-19)/(5)\\\\\therefore P(x,y)=((-18)/(5),(-19)/(5))

∴ PointP( x , y ) = ( -3.6, -3.8)

User Dennis Kaselow
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories