Question

a .6 kg ball has a speed of 2 m/s at point a and kinetic energy of 7.5 j at point b. determine the following: the balls speed

Answer 1

Given

m = 6kg, KE=7.5j, v=? (v= 2m/s not needed we only need "m" and "KE" )

Formula

K.E= (1/2)mv²

v²=((2)(K.E))/m

v=√(((2)(K.E))/m)

Solution:

v=√(((2)(7.5j))/6kg)

v=√((7.5kg(m/s)²)/(3kg)) (1j=1kg(m/s)²

v=√(2.5(m/s)²)

v=√(2.5)m/s Ans