Question

Minh has a coin collection of dimes and nickels worth $1.70. The number of nickels is four more than the number of dimes. How many of each coin does she have ?

Answer 1

The number of coins each she have are 10 dimes coin and 14 nickel coins.

Explanation:

Given:

Minh has a coin collection of dimes and nickels worth $1.70.

The number of nickels is four more than the number of dimes.

Now, to find each coins she have.

Let the number of dimes be
`x`.

And the number of nickels be
`4+x`.

As the value of dimes = $0.10, and the value of nickel = $0.05.

Now, according to question:

`0.10x+0.05(4+x)=1.70`

⇒
`0.10x+0.20+0.05x=1.70`

⇒
`0.15x+0.20=1.70`

Subtracting both sides by 0.20 we get:

⇒
`0.15x=1.50`

Dividing both sides by 0.15 we get:

⇒
`x=10`.

Number of dimes = 10.

Number of nickel =
`4+x=4+10=14.`

Therefore, the number of coins each she have are 10 dimes coin and 14 nickel coins.