The length in feet is (x - 80) feet
Solution:
The area in square feet of a rectangular field is
![x^2 - 140x + 4800](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ll45bhfi1r088a21pmguqzgwqejwtp8wg3.png)
The width, in feet, is x - 60
To find: length in feet
The area of rectangle is given as:
![\text {area of rectangle }=\text { length } * \text { width }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6qmxiw2xqc0ffvaw1awa442nx9kdxt0ead.png)
Now we can simplify area
area =
![x^2 - 140x + 4800](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ll45bhfi1r088a21pmguqzgwqejwtp8wg3.png)
-140x can be rewritten as -80x - 60x
![area = x^2 -80x -60x + 4800](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y1xni8fq5ggmh6c24p96xsqk6jx7q1qifp.png)
Taking "x" as common from first two terms and -60 as common from last two terms
area = x(x - 80) -60(x - 80)
Taking (x - 80) as common term
Area = (x - 80)(x - 60)
Substitute area = (x - 80)(x - 60) and width = (x - 60)
![(x-80)(x-60)=\text { length } *(x-60)\\\\length = ((x-80)(x-60))/((x-60))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gxmrv8aeh8y2oi73vebqsod9nvyv3zh782.png)
Cancelling (x - 60)
length = (x - 80)
Thus the length in feet is (x - 80) feet